2x^2+8x=136

Solution for 2x^2+8x=136 equation:

2x^2+8x=136

We move all terms to the left:

2x^2+8x-(136)=0

a = 2; b = 8; c = -136;
Δ = b2-4ac
Δ = 82-4·2·(-136)
Δ = 1152
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1152}=\sqrt{576*2}=\sqrt{576}*\sqrt{2}=24\sqrt{2}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-24\sqrt{2}}{2*2}=\frac{-8-24\sqrt{2}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+24\sqrt{2}}{2*2}=\frac{-8+24\sqrt{2}}{4}
$